Write the following cube in expanded form:- `[x-2/3y]^3`

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#### Solution

`[x-2/3y]^3 = x^3-(2/3y)^3-3(x)(2/3y)(x-2/3y)`

`= x^3-8/27y^3-2xy(x-2/3y)`

`= x^3-8/27y^3-2x^2y+4/3xy^2`

Concept: Algebraic Identities

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